Optimal. Leaf size=299 \[ \frac{2 b^2 c^3 \sqrt{c^2 x^2+1} \text{PolyLog}\left (2,e^{-2 \sinh ^{-1}(c x)}\right )}{3 \sqrt{c^2 d x^2+d}}-\frac{2 c^3 \sqrt{c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 \sqrt{c^2 d x^2+d}}+\frac{2 c^2 \sqrt{c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x}-\frac{b c \sqrt{c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )}{3 x^2 \sqrt{c^2 d x^2+d}}-\frac{\sqrt{c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x^3}-\frac{4 b c^3 \sqrt{c^2 x^2+1} \log \left (1-e^{-2 \sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 \sqrt{c^2 d x^2+d}}-\frac{b^2 c^2 \left (c^2 x^2+1\right )}{3 x \sqrt{c^2 d x^2+d}} \]
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Rubi [A] time = 0.427373, antiderivative size = 299, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 9, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.321, Rules used = {5747, 5723, 5659, 3716, 2190, 2279, 2391, 5661, 264} \[ -\frac{2 b^2 c^3 \sqrt{c^2 x^2+1} \text{PolyLog}\left (2,e^{2 \sinh ^{-1}(c x)}\right )}{3 \sqrt{c^2 d x^2+d}}+\frac{2 c^3 \sqrt{c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 \sqrt{c^2 d x^2+d}}+\frac{2 c^2 \sqrt{c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x}-\frac{b c \sqrt{c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )}{3 x^2 \sqrt{c^2 d x^2+d}}-\frac{\sqrt{c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x^3}-\frac{4 b c^3 \sqrt{c^2 x^2+1} \log \left (1-e^{2 \sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 \sqrt{c^2 d x^2+d}}-\frac{b^2 c^2 \left (c^2 x^2+1\right )}{3 x \sqrt{c^2 d x^2+d}} \]
Warning: Unable to verify antiderivative.
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Rule 5747
Rule 5723
Rule 5659
Rule 3716
Rule 2190
Rule 2279
Rule 2391
Rule 5661
Rule 264
Rubi steps
\begin{align*} \int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{x^4 \sqrt{d+c^2 d x^2}} \, dx &=-\frac{\sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x^3}-\frac{1}{3} \left (2 c^2\right ) \int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{x^2 \sqrt{d+c^2 d x^2}} \, dx+\frac{\left (2 b c \sqrt{1+c^2 x^2}\right ) \int \frac{a+b \sinh ^{-1}(c x)}{x^3} \, dx}{3 \sqrt{d+c^2 d x^2}}\\ &=-\frac{b c \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{3 x^2 \sqrt{d+c^2 d x^2}}-\frac{\sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x^3}+\frac{2 c^2 \sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x}+\frac{\left (b^2 c^2 \sqrt{1+c^2 x^2}\right ) \int \frac{1}{x^2 \sqrt{1+c^2 x^2}} \, dx}{3 \sqrt{d+c^2 d x^2}}-\frac{\left (4 b c^3 \sqrt{1+c^2 x^2}\right ) \int \frac{a+b \sinh ^{-1}(c x)}{x} \, dx}{3 \sqrt{d+c^2 d x^2}}\\ &=-\frac{b^2 c^2 \left (1+c^2 x^2\right )}{3 x \sqrt{d+c^2 d x^2}}-\frac{b c \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{3 x^2 \sqrt{d+c^2 d x^2}}-\frac{\sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x^3}+\frac{2 c^2 \sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x}-\frac{\left (4 b c^3 \sqrt{1+c^2 x^2}\right ) \operatorname{Subst}\left (\int (a+b x) \coth (x) \, dx,x,\sinh ^{-1}(c x)\right )}{3 \sqrt{d+c^2 d x^2}}\\ &=-\frac{b^2 c^2 \left (1+c^2 x^2\right )}{3 x \sqrt{d+c^2 d x^2}}-\frac{b c \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{3 x^2 \sqrt{d+c^2 d x^2}}+\frac{2 c^3 \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 \sqrt{d+c^2 d x^2}}-\frac{\sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x^3}+\frac{2 c^2 \sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x}+\frac{\left (8 b c^3 \sqrt{1+c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{e^{2 x} (a+b x)}{1-e^{2 x}} \, dx,x,\sinh ^{-1}(c x)\right )}{3 \sqrt{d+c^2 d x^2}}\\ &=-\frac{b^2 c^2 \left (1+c^2 x^2\right )}{3 x \sqrt{d+c^2 d x^2}}-\frac{b c \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{3 x^2 \sqrt{d+c^2 d x^2}}+\frac{2 c^3 \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 \sqrt{d+c^2 d x^2}}-\frac{\sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x^3}+\frac{2 c^2 \sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x}-\frac{4 b c^3 \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right ) \log \left (1-e^{2 \sinh ^{-1}(c x)}\right )}{3 \sqrt{d+c^2 d x^2}}+\frac{\left (4 b^2 c^3 \sqrt{1+c^2 x^2}\right ) \operatorname{Subst}\left (\int \log \left (1-e^{2 x}\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{3 \sqrt{d+c^2 d x^2}}\\ &=-\frac{b^2 c^2 \left (1+c^2 x^2\right )}{3 x \sqrt{d+c^2 d x^2}}-\frac{b c \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{3 x^2 \sqrt{d+c^2 d x^2}}+\frac{2 c^3 \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 \sqrt{d+c^2 d x^2}}-\frac{\sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x^3}+\frac{2 c^2 \sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x}-\frac{4 b c^3 \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right ) \log \left (1-e^{2 \sinh ^{-1}(c x)}\right )}{3 \sqrt{d+c^2 d x^2}}+\frac{\left (2 b^2 c^3 \sqrt{1+c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 \sinh ^{-1}(c x)}\right )}{3 \sqrt{d+c^2 d x^2}}\\ &=-\frac{b^2 c^2 \left (1+c^2 x^2\right )}{3 x \sqrt{d+c^2 d x^2}}-\frac{b c \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{3 x^2 \sqrt{d+c^2 d x^2}}+\frac{2 c^3 \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 \sqrt{d+c^2 d x^2}}-\frac{\sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x^3}+\frac{2 c^2 \sqrt{d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{3 d x}-\frac{4 b c^3 \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right ) \log \left (1-e^{2 \sinh ^{-1}(c x)}\right )}{3 \sqrt{d+c^2 d x^2}}-\frac{2 b^2 c^3 \sqrt{1+c^2 x^2} \text{Li}_2\left (e^{2 \sinh ^{-1}(c x)}\right )}{3 \sqrt{d+c^2 d x^2}}\\ \end{align*}
Mathematica [A] time = 0.629257, size = 278, normalized size = 0.93 \[ \frac{2 b^2 c^3 x^3 \sqrt{c^2 x^2+1} \text{PolyLog}\left (2,e^{-2 \sinh ^{-1}(c x)}\right )+2 a^2 c^4 x^4+a^2 c^2 x^2-a^2-a b c x \sqrt{c^2 x^2+1}-4 a b c^3 x^3 \sqrt{c^2 x^2+1} \log (c x)-b \sinh ^{-1}(c x) \left (-2 a \left (2 c^4 x^4+c^2 x^2-1\right )+b c x \sqrt{c^2 x^2+1}+4 b c^3 x^3 \sqrt{c^2 x^2+1} \log \left (1-e^{-2 \sinh ^{-1}(c x)}\right )\right )-b^2 c^4 x^4-b^2 c^2 x^2+b^2 \left (2 c^4 x^4-2 c^3 x^3 \sqrt{c^2 x^2+1}+c^2 x^2-1\right ) \sinh ^{-1}(c x)^2}{3 x^3 \sqrt{c^2 d x^2+d}} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.309, size = 2147, normalized size = 7.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{c^{2} d x^{2} + d}{\left (b^{2} \operatorname{arsinh}\left (c x\right )^{2} + 2 \, a b \operatorname{arsinh}\left (c x\right ) + a^{2}\right )}}{c^{2} d x^{6} + d x^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b \operatorname{asinh}{\left (c x \right )}\right )^{2}}{x^{4} \sqrt{d \left (c^{2} x^{2} + 1\right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}^{2}}{\sqrt{c^{2} d x^{2} + d} x^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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